Men's Running Shorts 7 inch Lightweight 2 Pack Gym Shorts with Pockets

Product details: Fabric type: 92% Nylon, 8% Spandex Care instructions: Machine Wash Origin: Imported Closure type: Drawstring

About this item: Men's workout shorts are made with high quality fabrics that are extremely soft, lightweight, comfortable, and breathable. The material wicks away sweat and dries quickly. Please refer to the size chart picture carefully before purchasing!

These men's training sports shorts feature a regular fit, elasticized waist with an adjustable drawstring, solid color, and 2 side hidden pockets. One side pocket has a zipper to prevent your phone, card, valuables, or mp3 player from falling out during exercise. The V cut hem design provides a comfortable fit and unrestrained movement for your legs.

These gym shorts are suitable for bodybuilding, training, boxing, workout, fitness, jogging, cycling, and other outdoor activities. They are also great for casual wear, home wear, beachwear, or outdoor living. These shorts can be a perfect gift for your male friends.

Care instructions: These shorts are easy to clean and retain their shape and color even after multiple washes. Machine wash cold, do not dry clean, tumble dry low with care. Please contact us if you have any questions.

Product Description: Men's Workout Athletic Shorts 7 inch Inseam. Men's training sports shorts with a regular fit, elasticized waist with adjustable drawstring, solid color, and 2 side hidden pockets.

Men's 7 Inch Running Shorts offer an athletic fit, perfect for running, training, weightlifting, crossfit, tennis, basketball, rugby, and more. If you prefer loose-fitting sports shorts, you can choose one size up.

You'll like: - Men's Workout Shorts - Men's Gym Shorts - Men's Zipper Polo Shirts - Men's Polo T-Shirts - Men's Shorts 7 inch Inseam - Men's Athletic Shorts - Men's Running Shorts

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.findAll(Arrays.asList(1, 2, 3)) = [1, 2, 3] .upto(5) = [1, 2, 3, 4, 5] findAll { it % 2 == 0 } = [2, 4] Java 8+ includes all the JavaScript Date/Moment features you mention. Repeated Characters-Count from Scanner.scan JAVA Once you start using Java 8 and its Stream API, the possibilities are endless. This statement. , the possibilities are endless..forEach((c, count) -> System.out.println(c + ": " + count));

public static void main(String[] args) { System.out.println(sumOfArithmeticSequence(1, 10, 1)); }

public static int sumOfArithmeticSequence(int min, int max, int step) { int count = ((max - min) / step) + 1; return count * (max + min) / 2; }

answer: 55

public static boolean isNumericUsingRegularExpression(String str) { return str.matches("-?\d+(\.\d+)?"); }

public static boolean isNumericUsingBuiltInMethods(String str) { if (str == null) { return false; } try { Double.parseDouble(str); } catch (NumberFormatException nfe) { return false; } return true; }

public static boolean isNumericUsingASCII(String str) { if (str == null) { return false; } int length = str.length(); for (int i = 0; i < length; i++) { if (!Character.isDigit(str.charAt(i))) { return false; } } return true; }.

public static void main(String[] args) { String testString = "123456"; System.out.println(isNumericUsingRegularExpression(testString)); System.out.println(isNumericUsingBuiltInMethods(testString)); System.out.println(isNumericUsingASCII(testString)); }

answer: true true true

public static List splitStringBySize(String str, int size) { List result = new ArrayList<>(); int start = 0; int length = str.length(); while (start < length) { result.add(str.substring(start, Math.min(length, start + size))); start += size; } return result; }

public static void main(String[] args) { String testString = "abcdefghij"; splitStringBySize(testString, 3).forEach(System.out::println); }

answer: abc def ghi j

public static void main(String[] args) { List list = Stream.of(1, 2, 3, 4, 5).collect(Collectors.toList()); System.out.println(list); // [1, 2, 3, 4, 5] }

public static void main(String[] args) { List oddNumbers = Stream.iterate(1, n -> n + 2) .limit(3) .collect(Collectors.toList()); System.out.println(oddNumbers); // [1, 3, 5] }

public static void main(String[] args) { List evenNumbers = IntStream.range(2, 6) .mapToObj(i -> i) .collect(Collectors.toList()); System.out.println(evenNumbers); // [2, 3, 4, 5] } For the above example, the code generates the below output:

[1, 2, 3, 4, 5]

cannot useString::split as in Java, delimiter is a regular expression. Provides startIndex and limit that can be used to manipulate the result.

public static void main(String[] args) { String testString = "0 1 2 3 4 5"; Arrays.stream(testString.split("\s", 3)) //.startsWith(2) or however many are needed, in case of this example, 3 .forEach(System.out::println); }

answer: 0 1 2 3 4 5 What will be output of following code?

public static int compareStrings(String string1, String string2) { return string1.compareTo(string2); }

answer: This method compares two strings lexicographically, and returns an integer value based on the result. It returns a negative value, zero, or positive value if the first string is less than, equal to, or greater than the second string respectively based on the lexicographical order. In case of this example with "World" and "Hello!" as inputs, it would return a positive value, since "World" is greater than "Hello!" in lexicographical order.

for printing result.

public static final LocalTime LOCAL_SESSION_TIME = LocalTime.now(); public static void main(String[] args) { System.out.println(LOCAL_SESSION_TIME); } The output of the code will be the local time when running the program. The output is not constant, as it will print the local time based on the time when the program is executed. This means that each time the program is executed, the output will show the current local time.

Output depends on the runtime at which the code is executed.

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